Table 15 Magic formulas for the fcc tetrahedron

Atoms

\(\frac {1}{6}n^{3} + n^{2} + \frac {11}{6}n + 1,~n\ge 1\)

Bonds

n³+3n²+2n, n≥1

cn=3

4, n≥1

cn=6

6n−6, n≥1

cn=9

2n²−6n+4, n≥1

cn=12

\(\frac {1}{6}n^{3} - n^{2} + \frac {11}{6}n -1,~n \ge {1}\)