Table 16 Magic formulas for the bcc tetrahedron

Atoms

\(\frac {1}{3}n^{3} + \frac {3}{2}n^{2} + \frac {13}{6}n + 1,~n\ge 1\)

Bonds

\(\frac {2}{3}n^{3} + 2n^{2} + \frac {4}{3}n,~n\ge 1\)

cn=1

4, n≥1

cn=2

6n−6, n≥1

cn=3

2n²−6n+4, n≥1

cn=4

\(\frac {1}{3}n^{3} - \frac {1}{2}n^{2} + \frac {13}{6}n -1,~n\ge 1\)